If the 3rd and 6th terms of an ap are 7 and 13 respectively find the 10th term
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Step-by-step explanation:
Given a3=7, a6=13, a10=?
a3=a+2d=7(1)
a6=a+5d=13 (2)
(2)-(1)
a+5d=13
-a+(-)2d=(-)7
3d=6
d=2.
.α=13-5d
=13-5*2=13-10
=3
a10=a+9d
=3+9*2
=3+18
α10=21.
hope it helps u.
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