If the 3rd and the 8th term of an A.P. are 8 and 3 respectively, then find the 11th term
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a+2d=8.....(i)
a+7d=3......(ii)
By subtraction
a+7d=3
_a+2d=8
—————————
5d= -5
d= -1; a=10
11th term is
=a+10d
Substituting the values
=10+10(-1)
=10-10
=0
11th term is 0
Hope it helps!!!!
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