If the 3rd and the 9th terms of an AP are 4 and -8 respectively, which term of this AP is zero. Please help me guys.
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Answer:
a3- 3rd term of AP
a9- 9th term if AP
a3 = a + 2d = 4 --------eq(1)
a9 = a + 8d = -8 --------eq(2)
eq(2) - eq(1) = 6d = -12
d = -2
therefore, eq(1) gives,
a + 2×-2 = 4 (d= -2)
a - 4 = 4
a = 8
a=8, d= -2, an= 0
an= a + (n-1)d
8+(n-1)×-2 = 0
(n-1)×-2 = -8
n-1 = -8/-2 = 4
n=4+1 = 5
n=5
5th term of this AP is 0.
hope it helps
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