If the 3rd term & 9th terms of an AP are 4 & -8 respectively, which term of the AP is zero
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A9 = 0
a + 8d = 0
a = -8d ...... (1)
Now, to prove,
a29 = 2a19
a + 28d = 2(a + 18d)
a + 28d = 2a + 36d
-8d + 28d = -16d + 36d
20d = 20d
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