If the 3rd term of an A.P.is 4 times of its 1st term and its 6th term is 17. find the series?
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Answer:
2,5,8,11,14,17,...........
Step-by-step explanation:
Given that in an AP , the third term is four times the first term
.
Let the first term be a and the common difference be d
.
⇒a+2d=4×a
⇒2d=3a
Given that the sixth term is 17
,
⇒a+5d=17
⇒2d
/3+5d=17
⇒d= 17
3
/17×17=3
Therefore we get d=3 and a= 3
So the series is 2,5,8,11,14,17,...........
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