Math, asked by hehhjeeheebddbbhshss, 11 months ago

If the 4th, 10th and 16th terms of a G.P. are x, y and z respectively. Prove that x,y,z are in G.P.​

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Answered by ritikaritikasaini
6

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Answered by Anonymous
3

\huge\mathfrak\red{Hello}

let first term of GP be a and common ratio be r

than 4th term is ar^3

10 th term is ar^9

16 the term is ar^15

ar^3,ar^9,ar^15

are in gp with common ratio r^6

hence proved.

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