Question

If the 4th,10th and 16th terms of a GP are x,y and z prove that x,y and z are in GP​

Answer 1

Step-by-step explanation:

fourth term , t4 = a(r) ^3 = x

t10 = a(r) ^9 = y

t16 = a(r) ^15 = z

Let, x, y, z are in gp then,

r' = y/x = z/y

this implies,

r' = (a(r) ^9 ) / (a(r) ^3) = (a(r) ^15) / (a(r) ^9)

= r^6 = r^6

Hence proved.

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