prove that A-B and B-A are disjoint
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Answer for this question is
A=35
B=20
A-B, means
35-20
=15
Whereas
B-A
20-35
= -15
Therefore
A-B and B-A are disjoint
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Pair wise disjoint means no two elements of any two sets are equal.
So,we have to proof:
(A−B)∩(B−A)=(A−B)∩(A∩B)=(B−A)∩(A∩B)=ϕLetxϵ(A−B)∩(B−A)∴xϵ(A−B)&xϵ(B−A)xϵA−(i)orx∈/B−(ii)xϵB−(iii)orx∈/A−(iv)
from(i)&(iv) we are at contradiction
Hence (A−B)∩(B−A)=ϕ
Now,let ∴xϵ(A−B)∩(A∩B)
xϵAorx∈/B
xϵAorxϵBSo,xϵAorxϵBorx∈/B
So,xϵBorx∈/B are at conradiction.
(A−B)∩(A∩B)=ϕ
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