If the 4th and 9th terms of a G.P are 54 and 13122 respectively then find the G.P
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Answered by
98
Heya dear !
The general formula for the nth term of a geometric progression is:
a(n) = ar^(n-1)
a : first term
r : common ratio
So, the terms of a geometric progression are:
a, ar, ar², ar^3, ar^4, etc.
Fourth term:
ar^3 = 54
Ninth term:
ar^8 = 13122
Dividing the 9th term by the 4th term:
ar^8 / ar^3 = 13122 / 54
r^5 = 243
r = 243^(1/5)
r = 3
Now we just need to figure the first term:
ar^3 = 54
Plug in r=3:
a(3^3) = 54
27a = 54
a = 54/27
a = 2
Answer:
a(n) = 2*3^(n-1)
2, 6, 18, 54, 162, 486, etc.
Hope this helps (:
The general formula for the nth term of a geometric progression is:
a(n) = ar^(n-1)
a : first term
r : common ratio
So, the terms of a geometric progression are:
a, ar, ar², ar^3, ar^4, etc.
Fourth term:
ar^3 = 54
Ninth term:
ar^8 = 13122
Dividing the 9th term by the 4th term:
ar^8 / ar^3 = 13122 / 54
r^5 = 243
r = 243^(1/5)
r = 3
Now we just need to figure the first term:
ar^3 = 54
Plug in r=3:
a(3^3) = 54
27a = 54
a = 54/27
a = 2
Answer:
a(n) = 2*3^(n-1)
2, 6, 18, 54, 162, 486, etc.
Hope this helps (:
AbhiramiGNath:
ur answer is amazing...
Answered by
13
Answer:
THE G.P. IS 2,6,18,54...............
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