If the 4th and the 9th terms of a geometric progression are 1/3 and 81 respectively, find the
first term.
Answers
Answered by
0
Answer:
-47. 8
Step-by-step explanation:
a4=1/3
a+3d=1/3 -(1)
a9=81
a+8d=81
a=81-8d -(2)
put eq2 in 1
a+3d=1/3
81-8d+3d=1/3
81-5d=1/3
-5d=1/3-81
-5d=1-243/3
-5d=-242/3
d=242/15=16.1
A=81-8d = 81-8(16.1)
81-128.8 = -47. 8
Similar questions