if the 5th term of an AP is 20 and 15th term is 50.then find the AP and its Nth term
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t5=20
t15=50
a+4d=20
a+14d=50
on subtracting both
10d=30
d=3
on putting this in equation we have
a+4d=20
a+12=20
a=8
Ap=8,11,14....
tn=8+(n-1)3
=8+3n-3
=5+3n
t15=50
a+4d=20
a+14d=50
on subtracting both
10d=30
d=3
on putting this in equation we have
a+4d=20
a+12=20
a=8
Ap=8,11,14....
tn=8+(n-1)3
=8+3n-3
=5+3n
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