If the 5th term of an AP is zero show that 33rd term is two times it's 19th term
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fifth term = a+4d= 0
so 33rd term = 2 × 19th term
a+ 32d = 2 × a+18d
a+ 32d = 2a + 36d
here 2a - a = 32d - 36d
a = - 4d
a+4d=0
so that is prove
so 33rd term = 2 × 19th term
a+ 32d = 2 × a+18d
a+ 32d = 2a + 36d
here 2a - a = 32d - 36d
a = - 4d
a+4d=0
so that is prove
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