If The 6th term of an a.p 37 and the sum of the first term is 147, find the ,first term And fifteen term
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Correct Question:-
If the 6th term of an AP is 37 and the sum of first 6 terms is 147 , find the first term and sum of first 15 terms.
Answer:-
Given:
6th term of an AP = 37
We know that,
nth term of an AP (a_n) = a + (n - 1)d
→ a + (6 - 1)d = 37
→ a + 5d = 37 -- equation (1)
And also given that,
Sum of first 6 terms (S_6) = 147
Sum of first n terms of an AP = n/2 * [ a + l (nth term)]
→ 6/2 * [ a + (37) ] = 147
→ 3(a + 37) = 147
→ 3a + 111 = 147
→ 3a = 147 - 111
→ 3a = 36
→ a = 36/3
→ a = 12
Substitute "a" value in equation (1).
→ 12 + 5d = 37
→ 5d = 37 - 12
→ 5d = 25
→ d = 25/5
→ d = 5
→ 15th term = 12 + (15 - 1)(5)
→ a_15 = 12 + 70
→ a_15 = 82
Sum of first 15 terms = 15/2 * [12 + 82 ]
→ S_15 = 15/2 * (94)
→ S_15 = 705
Hence, the first term of the given AP is 12 and the sum of first 15 terms is 705.
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