Question

if the 6th term of an Arithmetic sequence is 0, show that it's 26th term is double the 16th term.​

Answer 1

ans of following question is given

Answer 2

$t_{6} = 0\\ \\a + 5d = 0\\\\t_{16} = a + 15d = 0 + 10d = 10d\\\\t_{26} = a + 25d = 0 + 20d = 20d\\\\\\\frac{t_{26}}{t_{16}} = \frac{20d}{10d} = 2$

Hence Proved