if the 7th and 13th term of an AP be 34 and 64 respectively, then the 18 term is?
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Answer:
89
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a7=a+6d
=>a+6d=34------(1)
a13=a+12d
=>a+12d=64------(2)
Now,substract (2)from (1) we get,
d=5
So,a+6*5=34-----from (1)
a=4
Then ,a18=a+17d
a18=4+17*5
a18=4+85
a18=89
Therefore 18th term is 89.
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