If the 7th and 13th term of an arithmetic progression are 34 and 64 respectively yhen the common difference is
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Hey there !!
➡ Given :-
→ 7th term of AP ( ) = 34.
→ 13th term of AP ( ) = 64.
➡ To Find :-
→ The common difference (d).
➡ Solution :-
→ = 34.
=> a + ( n - 1 )d = 34.
=> a + ( 7 - 1 )d = 34.
=> a + 6d = 34........ (1).
And,
→ = 64.
=> a + ( n - 1 )d = 64.
=> a + ( 13 - 1 )d = 64.
=> a + 12d = 64........... (2).
▶ Substracte in equation (1) and (2), we get
a + 6d = 34.
a + 12d = 64.
(-)..(-)........(-).
__________
=> - 6d = - 30.
=> d =
✔✔ Hence, it is proved ✅✅.
____________________________________
THANKS
#BeBrainly.
➡ Given :-
→ 7th term of AP ( ) = 34.
→ 13th term of AP ( ) = 64.
➡ To Find :-
→ The common difference (d).
➡ Solution :-
→ = 34.
=> a + ( n - 1 )d = 34.
=> a + ( 7 - 1 )d = 34.
=> a + 6d = 34........ (1).
And,
→ = 64.
=> a + ( n - 1 )d = 64.
=> a + ( 13 - 1 )d = 64.
=> a + 12d = 64........... (2).
▶ Substracte in equation (1) and (2), we get
a + 6d = 34.
a + 12d = 64.
(-)..(-)........(-).
__________
=> - 6d = - 30.
=> d =
✔✔ Hence, it is proved ✅✅.
____________________________________
THANKS
#BeBrainly.
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