Question

if the 7th and 13th terms of an AP are 34 and 64 respectively then its 18th term is ​

Answer 1

Answer:

Step-by-step explanation:

T7 = 34

=> a+6d = 34------(1)

T13 = 64

=> a+12d = 64 ------(2)

On subtracting equation 1 from 2, we get

6d = 30

=> d = 5

a = 4

T18 = a+17d

= 4+ 17*5

= 4+85

= 89

MARK IT THE BRINALEIST

Answer 2

Solution

=> T7 = 34

=> a + 6d = 34 – eq (1)

=> T13 = 64

=> a + 12d = 64 – eq (2)

Equation (1) ,, (2)

=> 6d = 30

=> d = 30

=> d = 3

=> a = 4

Hence

=> T18 = a + 17 d

=> 4 + 17 ° 5

=> 4 + 85

=> 89