If the 8th term of an ap is 31 and 5th term 16 more 11th term.
find the AP.
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Answer:
nth term of AP is
a+(n-1)d
a=first term
d= common difference
given
31= a+(8–1)d
and
16=a+(15–1)d
31= a+7d
and
16=a+14d
solving these two simeltenious equations
multiple first equation by 2
62=2a+14d
deduct second equation from this
46=a
substitute it in equation 1
16=46+14d
16–46=14d
-30=14d
d=(-30/14
d=-2.1429
a= 46
2nd term= 46×-2.1429
3rd term= 46+(3–1)×-2.1429
Step-by-step explanation:
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