Question

If the 9th term of an arithmetic progression is zero then show that the 29th term is twice the 19th term....... Plz correct answer..... Step by step solution......

Answer 1

Answer:

Substituting n = 9 in this formula:

20d = 20d. Therefore, it is proved that the 29th term is twice the 19th term when the 9th term is 0.

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Answer 2

Answer:

Here is the answer

Step-by-step explanation:

Given

a9=0

a9=a+8d

0=a+8d--->(1)

Given that

a19=a+18d

--->a+10d+8d---(2)

a29=a+28d

--->a+20d+8d---(3)

From (2)and (3)

a29=20d+0(From1)=2*a19=10d+0(From1) Given that a9=0

hence the a29=2*a19

hence Proved

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