if the 9th term of AP is zero then prove that its 29th term is twice its 19th terms
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hello
let 1st term = a
and common difference=d
so a+8d=0 _______(1)
and
29th term = a+28d = -8d+28d=20d (from 1)
and 19th term= -8d +18d =10d
so 29th term = 20d =2×10d = 2×(19th term)
hence proved
thanks
let 1st term = a
and common difference=d
so a+8d=0 _______(1)
and
29th term = a+28d = -8d+28d=20d (from 1)
and 19th term= -8d +18d =10d
so 29th term = 20d =2×10d = 2×(19th term)
hence proved
thanks
geetasharma3266:
tysm!:)
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