If the abscissa of point A is two times the ordinate of point B, find the coordinates of point B
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givenx=2y,where(x,y)isco−ordinateofAAB=5(x−10)2+(y−0)2=5(2y−10)2+y2=524y2−40y+100+y2=255y2−40y+75=0y2−8y+15=0y2−5y−3y+15=0y(y−5)−3(y−5)=0(y−3)(y−5)=0∴y=3ory=5Ify=3thenx=6∴point(6,3)Ify=5thenx=
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