If the absolute value of x is 9.8. Then the number of integers lie between the possible value
of x is-- PLZ ANSWER
Answers
Given :- If the absolute value of x is 9.8. Then the number of integers lie between the possible value of x is ?
Solution :-
given that,
→ | x | = 9.8
So,
→ x = 9.8 , if x ≥ 9.8 .
or,
→ x = -9.8 , if x ≤ - 9.8 .
Than, Possible values of x are (9.8) or (-9.8).
Now, we know that,
- A integer is any number that is not either a decimal or a fraction .
Therefore,
Number of integers between 9.8 and (-9.8) are = 9, 8, 7, 6 , 5 , 4 , 3 , 2 , 1 , 0, -1 , -2 , -3, -4, -5, -6, -7, -8 and -9. = Total 19 . (Ans.)
Hence, the number of integers lie between the possible value of x is 19.
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If the sum of 3 natural numbers a,b, and c is 99 and a has 3 divisors then what will be the minimum value of b+c.
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1. Find the values of A and B if the given number 7A5798B8 is divisible by 33.
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ok it's very easy it's answer is 19