if the adjacent angles of parallelogram are (2x-5) & (3x+10), find the angles of parallelogram
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Since adjacent angles of parallelogram are supplementary(2x+5)+(3x+10)=1805x+15=1805x=180-15x=165/5x=33Since we found the x value we can now find the angles of the parallelogram2(33)+5 = 713(33)+10 = 109
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As we know that sum of angles of a pentagon= 540
Since, opposite angles are equal in a ||°gm
2x-5+3x+10+2x-5+3x+10=540
5x+5+5x+5=540
10x+10=540
10x=540-10
10x=530
x=530/10
x=53
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