Question

If the ages of kissi and essinam is3:5 and that of essinam and lariba is 3:5 and the sum of all 3 ages is 147 years .What is the difference between the oldest and the youngest age

Answer 1

Answer:

Step-by-step explanation:

Let kissi= A

Esinam=B

Larbi=C

Then A:B=3:5

B:C=3:5

We equalize be by multiplying the first ratio by 3 and the second ratio by 5. It implies that,

A:B=3x3:5x3=9:15

B:C=3x5:5x5=15:9

Now we can write A:B:C as 9:15:25

Total ratio =45

Kissi's age = 9/45 x 147 = 27 years

Esinam's age = 15/45 x 147 = 45years

Larbi's age = 9/45 x 147 = 75 years

Difference of oldest and youngest = 75 - 27 = 48 years