Question

if the altitude drawn from two vertices of a triangle two opposite sides are equal prove that triangle is isosceles​

Answer 1

Answer:

Step-by-step explanation:

Answer 2

In △ABE and △ACF

∠AEB=∠AFC (90⁰ each)

∠BAE=∠CAF (common angle)

∠ABE=∠ACF using angle sum property

BE=CF

⇒ △ABE≅△ACF

⇒ AB=AC

∴ △ABC is an isosceles tangent as two sides are equal to each other