Question

if the altitude of the sun is at 60 degree, then the height of the vertical tower that will cast a shadow of length 30 meter is

Answer 1

according to the question:->

we have to find the height as we have a base of 30 meter length .

as Base. =cot

Perpendicular

as cot 60 is

$\frac{1}{ \sqrt{3} }$

base = prpendicular ÷√3

$b \sqrt{3} = 30.$

$b = \frac{30}{ \sqrt{3} } .$

$on \: rationalising \: it \: is \: = \frac{30 \times \sqrt{3} }{ \sqrt{3 } \times \sqrt{3} } . => \frac{30 \sqrt{3} }{3} .=> \sqrt[10]{3}$

as

$10 \sqrt{3}$

is the height of the vertical tower.

mark it as a brainlist answer.