if the altitudes drawn from two vertices of a triangle to opposite sides are equal . prove that triangle is isoscels
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harsh7483:
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In △ABE and △ACF
∠AEB=∠AFC (90⁰ each)
∠BAE=∠CAF (common angle)
∠ABE=∠ACF using angle sum property
BE=CF
⇒ △ABE≅△ACF
⇒ AB=AC
∴ △ABC is an isosceles tangent as two sides are equal to each other
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