Question

If the ammeter in the given circuit reads 2A, thr resistance R is

Answer 1

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Answer 2

Answer:

The resistance is R = 1 Ω

Explanation:

In this circuit,there are three resistance $R_{1}$ = 3 Ω , $R_{2}$ = 6 Ω  and R.

Now, $R_{1}$ and $R_{2}$ both are parallel to each other.

According to the parallel condition of resistance,we can write that

                           $\frac{1}{R_{eq} } = \frac{1}{R_{1}} + \frac{1}{R_{2}}$

                       →  $R_{eq} = \frac{R_1 R_2}{R_1+R_2}$  $= \frac{3*6}{3+6}$

                                                  = $\frac{18}{9}$  = 2 Ω

Again, $R_{eq}$  and R are series connection and current(I) through  the circuit is 2A  and supply voltage(V) is 6V.

Therefore,

                      $R_{eq} + R = \frac{V}{I}$         [Using Ohm's law,V= IR]

                   → 2 +  R = $\frac{6}{2}$  = 3

                  → R = (3-2) = 1 Ω  [Ans]