if the amount of heat required to raise temperature of 2 moles monoatomic ideal gas by 1 degree celsius at constant pressure is 10 cal , then change in internal energy of gas is(R=2cal/k-mol
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Answer:
Q = ( n ) ( Cvm ) ( T2 - T1 )
For a monataomic ideal gas :
Cvm = ( 3/2 ) ( R ) = ( 3/2 ) ( 8.313 J/mol - K ) = 12.47 J/mol - K
Q = ( 2 mol ) ( 12.47 J/mol - K ) ( 10 C )
Q = 249 J <-------------------
Explanation:
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the answer is above and question is from aiats test series 3
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