If the angle brtween gwo tangents drawn from an external point p to a circle of radis a and cebtre o is 60 degree then find the length of op
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∠OAP = 90
We know that if 2 tangents are drawn from an external point, then they are equally inclined to the line segment joining the centre to that point.
So, ∠OPA = 12∠APB = 12×60° = 30°
According to the angle sum property of triangle-
In ∆AOP,∠AOP + ∠OAP + ∠OPA = 180°⇒∠AOP + 90° + 30° = 180°⇒∠AOP = 60°
So, in triangle AOP
tan angle AOP = AP/ OA
√ 3= AP/a
therefore, AP = √ 3a
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