If the angle of a quadrilateral are equal, prove that it is a rectangle.
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Answer:
let ABCD a parallelogram
to prove ABCD is a rectangle
in ∆ABC and ∆DCB
AB= DC (opposite sides of parallelogram are equal)
BC=BC ( common)
AC= DB ( given)
therefore,
∆ABC is congruent to ∆DBC (sss congruent rule)
hene prove
hope it helps u thanks
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