If the angle of elevation of a tower from a distance of 100 meters from its foot is 60°, then the height of the tower is
A. 100√3m
B. 100√3m
C. 50√3m
D.200/√3m
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Answer:
100√3will be the correct answer for ur question
Answered by
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B. 100√3m
Step-by-step explanation:
We find that ABC is a triangle with AC as the hypotenuse and angle B is 90 degrees. Given that angle C is 60 degrees. Let x be the height of the tower, which is AB.
AB = opposite = x
BC = adjacent = 100m
So tan 60 = Opposite/ adjacent = x/100
√3 = x/100
Therefore x = 100√3m
Option B is the answer.
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