Question

If the angle of elevation of a tower from a distance of 100 meters from its foot is 60°, then the height of the tower is
A. 100√3m
B. 100√3m
C. 50√3m
D.200/√3m

Answer 1

Answer:

100√3will be the correct answer for ur question

Answer 2

B. 100√3m

Step-by-step explanation:

We find that ABC is a triangle with AC as the hypotenuse and angle B is 90 degrees. Given that angle C is 60 degrees. Let x be the height of the tower, which is AB.

AB = opposite = x

BC = adjacent = 100m

So tan 60 = Opposite/ adjacent = x/100

   √3 = x/100

 Therefore x = 100√3m

Option B is the answer.