Math, asked by SoulStealer1625, 11 months ago

If the angle of elevation of a tower from a distance of 100 meters from its foot is 60°, then the height of the tower is
A. 100√3m
B. 100√3m
C. 50√3m
D.200/√3m

Answers

Answered by manasbhatt69
0

Answer:

100√3will be the correct answer for ur question

Answered by topwriters
1

B. 100√3m

Step-by-step explanation:

We find that ABC is a triangle with AC as the hypotenuse and angle B is 90 degrees. Given that angle C is 60 degrees. Let x be the height of the tower, which is AB.

AB = opposite = x

BC = adjacent = 100m

So tan 60 = Opposite/ adjacent = x/100

   √3 = x/100

 Therefore x = 100√3m

Option B is the answer.

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