Question

If the angle of elevation of the bulding from a distance 100 meter of its foot 60°.Find the height of the building?

Answer 1

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Answer 2

$\blue{\bold{\underline{\underline{Answer:}}}}$

$\green{\therefore{\text{Height\:of\:building=173.2\:m}}}$

$\orange{\bold{\underline{\underline{Step-by-step\:explanation:}}}}$

• In the given question information given about If the angle of elevation of the bulding from a distance 100 meter of its foot 60°.

• We have to Find the height of building.

$\green{\underline \bold{Given :}} \\ : \implies \text{Angle of elevation of building= }60^{\circ} \\ \\ \red{\underline \bold{To \: Find:}} \\ : \implies \text{Height\:of\:building= ?}$

• According to given question :

$\text{Let\:Height\:of\:tower\:be\:x}\\\\ \bold{In \: \triangle \: ABC} \\ : \implies tan\:\theta=\frac{\text{perpendicular}}{\text{base}}\\ \\ : \implies tan\:60^{\circ} = \frac{AB}{BC} \\ \\ : \implies \sqrt{3}=\frac{AB}{100}\\ \\ \green{: \implies AB=100\sqrt{3}\:m}\\ \\ \green{\therefore \text{height \: of \: building =173.2\:m}}$