Question

If the angle theta is an acute angle and cos^2 theta+1/8=sin^2 theta, find theta.

Answer 1

Step-by-step explanation:

let the theta be 'a'

cos^2(a)+1/8=sin^2(a)

1/8= sin^2(a)-{1-sin^2(a)}

1/8=sin^2(a)-1+sin^2(a)

1/8+1=2sin^2(a)

9/8= 2sin^2(a)

9/16 s= sin^(a)

sin(a)= 3/4

(a) = sin^-1{3/4}