Question

If the angles (4x+4°)and (6x-4°)are supplementry angles,find the value of X.

explain step by step​

Answer 1

Answer:

ATQ

(4x + 4 °) + (6x - 4 °) = 180°

4x + 4 + 6x -4 = 180 °

10x = 180°

x = 18°

Answer 2

Question:-

If the angles (4x+4°)and (6x-4°)are supplementry angles,find the value of X.

Answer:-

• The value of x is 18°.

Solution:-

• Sum of angles = 180° ( Supplementary angles)
• First angle = 4x + 4 °
• Second angle = 6x – 4 °

$\large{ \tt : \implies \: \: \: \: ( 4x + 4 )° + ( 6x – 4 )°= 180 °}$

$\large{ \tt : \implies \: \: \: \: 10x°= 180 °}$

$\large{ \tt : \implies \: \: \: \: x = \frac{180}{10} °}$

$\large{ \tt : \implies \: \: \: \: x°= 18°}$

• The value of x is 18°.

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• First angle = 4x + 4 = 4(18) + 4 = 76°
• Second angle = 6x – 4 = 4(18) – 4 = 104°

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