if the angles A,B and C of a triangle ABC are in A.P then find the value of cosB
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Answer:0.5
Step-by-step explanation:
Consider the angles such that
A=x-d
B=x
C=x+d
d is the common difference(since the angles are in AP).
Since A+B+C=180degrees
x+d+x+x-d=180
3x=180
x=60 degrees=B
Therefore,
cosB=cos60=0.5.
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