Question

if the angles a b c are in a.p. then sinA+sinC/cosA +cosc in angle​

Answer 1

Answer:

Given that in ΔABC , ∠A,∠B,∠C are in increasing A.P. then we have

∠B−∠A=∠C−∠B

2∠B=∠A+∠C

But, in ΔABC , ∠A+∠B+∠C=π⟹∠A+∠C=π−∠B

2∠B=π−∠B

3∠B=π

∠B=π3

∴sinB=sinπ3=3√2

HOPE IT WILL HELP YOU FRIEND.....

PLZ FOLLOW ME....

AND ALSO MARK .....