If the angles of a quadrilateral are x,(x-20),(x-30)and (x+10);find the value of x
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The sum of all angles of a quadrilateral is 360°.
So,
x+x-20+x-30+x+10 = 360°
4x-40 = 360°
x-10 = 90°
x = 100°
So,
x+x-20+x-30+x+10 = 360°
4x-40 = 360°
x-10 = 90°
x = 100°
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