If the angles of a triangle ABC are in the ratio 2:3:4,find the measures of the angles A,B and C.
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Answered by
7
let the angles be
2x , 3x, 4x
applying angles sum property
now,
2x+3x+4x=180
9x=180
X=180/9
X= 20
so the angles will be 2x =2×20=40
3x=3×20=60
4x=4×20=80
hope this will help you
2x , 3x, 4x
applying angles sum property
now,
2x+3x+4x=180
9x=180
X=180/9
X= 20
so the angles will be 2x =2×20=40
3x=3×20=60
4x=4×20=80
hope this will help you
NikhilRajput0009:
hello
Answered by
6
!!•••••••☆☆ Hey mate ☆☆•••••••!!
Given :- angles are in the ratios 2:3:4
let the ratios be 2x , 3x and 4x
then,
2x + 3x + 4x = 180° ( sum of all angles in a triangle is 180°)
9x = 180°
x = 180/9
x = 20°
hence,
angle A = 2×20 = 40°
angle B = 3×20 = 60°
angle C = 4×20 = 80°
>>--------☺️--------<<
hope it will help you ✌️✌️
Given :- angles are in the ratios 2:3:4
let the ratios be 2x , 3x and 4x
then,
2x + 3x + 4x = 180° ( sum of all angles in a triangle is 180°)
9x = 180°
x = 180/9
x = 20°
hence,
angle A = 2×20 = 40°
angle B = 3×20 = 60°
angle C = 4×20 = 80°
>>--------☺️--------<<
hope it will help you ✌️✌️
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