If the angles of a triangle are in ratio 3:4:5 then the sides are in the ratio
(A) 3:4:5
(B) (2)^1/2:(6)^1/2 : (3) ^1/2+1
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Hey there!
We know that, Sum of angle in a triangle= 180 °
3x + 4x + 5x = 180
12x = 180
x = 15°
Angles are 45 , 60 , 75 .
According to Law of sines :
a/sinA = b/sinB = c/sinC .
a/sinA = b/sinB.
a/(1/√2 ) = b/ (√3/2)
√2a = 2b/√3
a/b = √2 : √3
a/b = 2 : √6
____________________________________________
b/sin60 = c/sin75
2b/√3 = 2√2c /( √3 + 1 )
b/√3 = √2c / √3 + 1
b /c = √6 / √3 + 1
Now, a : b : c = 2 : √6 : √3 + 1 .
Hope helped!
We know that, Sum of angle in a triangle= 180 °
3x + 4x + 5x = 180
12x = 180
x = 15°
Angles are 45 , 60 , 75 .
According to Law of sines :
a/sinA = b/sinB = c/sinC .
a/sinA = b/sinB.
a/(1/√2 ) = b/ (√3/2)
√2a = 2b/√3
a/b = √2 : √3
a/b = 2 : √6
____________________________________________
b/sin60 = c/sin75
2b/√3 = 2√2c /( √3 + 1 )
b/√3 = √2c / √3 + 1
b /c = √6 / √3 + 1
Now, a : b : c = 2 : √6 : √3 + 1 .
Hope helped!
HappiestWriter012:
welcies bro
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