If the angles of a triangle measures (x+40)⁰,(2x+20)⁰ and 3x⁰,find all the angles of a triangle. Also state which type of triangle is this. and
answer should be :- 60⁰,60⁰,60⁰; acute - angled triangle; pls answer it step by step
Answers
Step-by-step explanation:
Given:-
the angles of a triangle measures (x+40)⁰,(2x+20)⁰ and 3x⁰
To find:-
Find all the angles of a triangle.
Solution:-
Given that:
The angles of a triangle are
(x+40)°
(2x+20)°
3x°
We know that
"The sum of all angles in a triangle is equal to 180°".
=>(x+40)° + (2x+20)° + 3x° = 180°
=>(x°+2x°+3x°) + (40°+20°) = 180°
=>6x° + 60° = 180°
=>6x° = 180° - 60°
=>6x° = 120°
=> x° = 120°/6
=>x° = 20°
The value of x°= 20°
Now,
The value of (x+40)°= 20°+40° = 60°
The value of (2x+20)° = 2(20°)+20° = 40°+20°=60°
The value of 3x° = 3(20°)=60°
Answer :-
The angles of the given triangle are
60° , 60° , 60°
The triangle is an acute angled triangle.
Since each angle is less than 90°
Used formulae:-
- The sum of all angles in a triangle is 180°
- All angles are acute the triangle is called an acute angled triangle
- If an angle between 0° and 90° is called an acute angle
- In an equilateral triangle each angle is equal to 60°
Step-by-step explanation:
Let first angle be = x+40°
Second angle = 2x+20°
Third angle = 3x°
Since the sum of angles in a triangle = 180°
Therefore forming an equation
(x+40) + (2x+20) + 3x = 180
= x = 20
Therefore first angle = 20+40 = 60°
Second angle = 2×20+20 = 60°
Third angle = 3×20 = 60°
Therefore the triangle is an equilateral triangle as sum of the angles is 180°
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