if the angles of triangle are 3x degree,[2x-7degree] and [4x-11 degree,then find the value of x and also angles
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Answered by
2
as the sum of internal angle of a triangle =180°
so,
3x+2x-7+4x-11=180°
9x=180°+18°
9x=198°
x=22°
I angle =66°
II angle =37°
III angle =77°
HOPE IT HELPS
THANK YOU.
so,
3x+2x-7+4x-11=180°
9x=180°+18°
9x=198°
x=22°
I angle =66°
II angle =37°
III angle =77°
HOPE IT HELPS
THANK YOU.
Answered by
0
3x+ 2 x - 7 + 4 x - 11= 180°
9 x - 18 = 180
9 x = 180 + 18
9 x = 198
x = 198/ 9
9 x - 18 = 180
9 x = 180 + 18
9 x = 198
x = 198/ 9
Kmg13teen:
Sorry for Half answer but due to my mistake I post it but just put the value of x in each angle you will get your all angles
here x = 22
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