Question

If the angular speed of a particle in UCM is 20 pie rad/s , what is the period of UCM of the particle ?

Answer 1

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Answer 2

Given :

Angular speed (ω) = 20$\pi$ rad/sec

To Find :

The period of uniform circular motion

Solution :

We know, ω = $\frac{2\pi }{T}$  (where ω = angular speed; T = Time period)

or,          20$\pi$ = $\frac{2\pi }{T}$

or,            T   = $\frac{1}{10}$

∴             T   = 0.1 sec

∴ The Time period of Uniform Circular Motion of the particle is 0.1 sec.