Question

if the annual increase in the population of a city be 4% and the present population be 17576,what was it three years ago?​

Answer 1

Answer:

p = 17576

r = 4%

t = 3

A = 17576(100/100+4)³

= 17576( 100/104)³

= 17576× 100/104×100/104×100/104

= 17576× 50/52×50/52×50/52

= 15625

Answer 2

Given:

If the annual increase in the population of a city be 4%.

The present population be 17576.

To find:

The population of a city before three years.

Solution:

The annual increase in the population of a city be 4%.

The present population be 17576.

Let 'x' be the population before three years.

We can find the population by using the following formula,

Population = P $(1 +\frac{r}{100})^{n}$

Present population = 17576

P = x

r = 4%

n = 3 years

17576 = x $(1 +\frac{4}{100})^{3}$

17576 = x $(\frac{100+4}{100})^{3}$

17576 = x $(\frac{104}{100})^{3}$

17576 = x $(1.04)^{3}$

17576 = x (1.124864)

x = $\frac{17576}{1.124864}$

x = 15625

The population three years ago was 15625 .

Final answer:

The population of a city before three years was 15625