Question

If the area of a parallelogram is 68 sq . cm, then find the area of triangle from the area of parallelogram​

Answer 1

Answer:

♧ Given:

Area of the parallelogram = 68 sq . cm

♧ To find:

To find the area of the triangle

♧ Taken:

Let the base and height of the parallelogram be 2x

$HB=AP$

HB = Height and base

To find the area of the triangle :

$At=\frac{H×B}{2}$

Where,

At = Area of the triangle

H = Height

B = Base

♧ Concept:

To find the area of the triangle. Then first find the base and height of the parallelogram.

Height and base :

>> 2x = 68 sq . cm

>> x = 68/2

>> x = 34

So , the height of the parallelogram is 34 sq . cm

Now , find the base . By dividing height by area .

>> 68 sq . cm / 34 sq . cm

>> 2 sq . cm

So , the base of the parallelogram is 2 sq . cm .

♧ Solution:

Area of the triangle:

$\implies{At=\frac{34 × 2}{2}}$

$\implies{At=\frac{68}{2}}$

$\implies{At=34 cm}$

♧ Answer:

So , the area of the triangle is 34 cm .

♧ Extra information:

To find the area of the parallelogram:

$Ap=H×B$

Where,

Ap = Area of the parallelogram

H = Height

B = Base

To find area of the rectangle:

$Ar=L×B$

Where,

Ar = Area of the rectangle

L = Length

B = Breadth

To find the area of the square:

$As=S×S$

Where,

As = Area of the square

S = One side of the square