Math, asked by Bhanupartap3586, 1 year ago

If the area of a rectangle is increased by 32% and its breadth increased by 20%, what is the percentage increase in its length?

Answers

Answered by TPS
81
Initial length = L
initial breadth = B
initial area = LB

Area increased by 32%

new area = LB + 32/100 × LB = LB + 0.32LB = 1.32LB

new breadth = B + 20/100 B = 1.2B

New length = new area/new breadth = 1.32LB/1.2B = 1.1L

Increase in length = 1.1L - L = 0.1L

% increase = 0.1L/L × 100 = 10%
Answered by Brainlybarbiedoll
111
Hy mate ur answer in the attachment...☺️
Attachments:

SillySam: nice answer sista......xD
Brainlybarbiedoll: han chuhiya hun naa donkey ki behna jo hun
Brainlybarbiedoll: xD
Kanchan57: Amāziñg āñswēr
Brainlybarbiedoll: ☺️❤️
Brainlyaccount: awesome answer ☺☺♥ ♥ ♥
loveudolly813: bad answer
Similar questions