If the area of a rectangle is increased by 32% and its breadth increased by 20%, what is the percentage increase in its length?
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Initial length = L
initial breadth = B
initial area = LB
Area increased by 32%
new area = LB + 32/100 × LB = LB + 0.32LB = 1.32LB
new breadth = B + 20/100 B = 1.2B
New length = new area/new breadth = 1.32LB/1.2B = 1.1L
Increase in length = 1.1L - L = 0.1L
% increase = 0.1L/L × 100 = 10%
initial breadth = B
initial area = LB
Area increased by 32%
new area = LB + 32/100 × LB = LB + 0.32LB = 1.32LB
new breadth = B + 20/100 B = 1.2B
New length = new area/new breadth = 1.32LB/1.2B = 1.1L
Increase in length = 1.1L - L = 0.1L
% increase = 0.1L/L × 100 = 10%
Answered by
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Hy mate ur answer in the attachment...☺️
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SillySam:
nice answer sista......xD
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