Question

If the area of a rectangle is p^2 - 4 and its length is p +2, then find its breadth. very important for exam .please

Answer 1

mark brainliest plzzzzzz

Answer 2

$\mathfrak{Answer:}$

(P - 2).

$\mathfrak{Step-by-Step\:Explanation:}$

$\underline{\bold{Given\:in\:the\;Question:}}$

• Area of the rectangle = P² - 4 .
• Its length = P + 2.

$\underline{\bold{To\:find;}}$

• Breadth of the rectangle = ?

$\bold{Solution:}$

We know that ,

$\boxed{\bold{Breadth=\dfrac{Area\:of\:rectangle}{Length}}}\\\\\\\tt{=\dfrac{p^2-2^2}{p+2}}\\\\\\\boxed{\bold{a^2-b^2=(a+b)(a-b)}}\\\\\\\tt{=\dfrac{(p+2)(p-2)}{p+2}}\\\\\\\tt{=p-2.}\\\\\\\boxed{\boxed{\bold{Breadth=p-2.}}}$