if the area of a rectangular field is( x^2-11x-42)and its length is (x-3). find the breadth of the field.
Answers
Answer:
rectangle, the distance around the outside of the rectangle is known as perimeter. A rectangle is 2-dimensional; however, perimeter is 1-dimensional and is measured in linear units such as feet or meter etc.
The perimeter of a rectangle is the total length of all the four sides.
Perimeter of rectangle = 2L + 2W.
Example 1: Rectangle has the length 13 cm and width 8 cm. solve for perimeter of rectangle.
Solution:
Given that:
Length (l) = 13 cm
Width (w) = 8 cm
Perimeter of the rectangle = 2(l + w) units
P = 2(13 + 8)
P = 2 (21)
P = 42
Thus, the perimeter of the rectangle is 42 cm.
Example 2: If a rectangle's length is 2x + 1 and its width is 2x – 1. If its area is 15 cm2, what are the rectangle's dimensions and what is its perimeter?
Solution:
We know that the dimensions of the rectangle in terms of x:
l = 2x + 1
w = 2x – 1
Since the area of a rectangle is given by:
A = l * w
We can substitute the expressions for length and width into the equation for area in order to determine the value of x.
A = l * w
15 = (2x + 1) (2x -1)
15 = 4x2 – 1
16 = 4x2
x = ±2
Note that the value of x must be positive and therefore in our case, the value of x is 2. And now we have:
l = 5 cm
w = 3 cm
Therefore, the dimensions are 5cm and 3cm.
Now, substituting these values in the formula for perimeter, we will get
P = 2l + 2w
P = 2(5)+2(3)
P = 10+6
P = 16 cm
Example 3: Find the area and the perimeter of a rectangle whose length is 24 m and width is 12m?
Solution:
Given that:
length = L = 24m
width = W = 12m
Step-by-step explanation: