If the area of a rhombus is 96 cm sq and one of its diahonals is 16 cm,find its perimeter.
Answers
Answered by
79
area of rhombus = 1/2 d1 d2
96= 1/2 x 16 x d2
d2= 12 cm
perimeter is given by 2(d1^2 + d2^2)^1/2
2(144+256)^1/2
2(400)^1/2
2x20=40 cm
96= 1/2 x 16 x d2
d2= 12 cm
perimeter is given by 2(d1^2 + d2^2)^1/2
2(144+256)^1/2
2(400)^1/2
2x20=40 cm
sam243:
Wrong
Answered by
16
The steps are:
96= 16*diagonal 2 /2
96= 8*diagonal 2
96/8=Diagonal 2
=12
The perimeter is 48.
96= 16*diagonal 2 /2
96= 8*diagonal 2
96/8=Diagonal 2
=12
The perimeter is 48.
Wrong
How is it wrong?
Oh sorry perimeter is 40cm
how did u get perimeter =40 plz , explain
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