If the area of a sector is 5/18 of the area of the circle, find the angle subtended by
the sector at the center.
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Answered by
23
Answer: Given Area of Sector= 5/18 area of circle We know that, Area of sector = ∅/360 x π r2
∅/360 x π r2 = 5/18 x π r2
∅/360 = 5/18
∅ = 5 x 360/ 18 = 5 x 20 = 100 Dergree
∅ = 100 degree
Therefore, The angle subtended by the sector is = 100 degree
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Answered by
12
Answer:
Hello, Friend
Step-by-step
Area of a sector=(∅/360)×πr²
area of circle=πr²
So, as per the question
(∅/360)×πr²=(5/18)πr²
cancel πr² on both sides
∴(∅/360)=(5/18)
by cross multiplication we get
∅×18=5×360
18×∅=1800
∅=1800/18=100°
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